get a list of directory names with find

Question

I know I can do this to get a list of directory names:

find . -type d -maxdepth 1 

but the output looks like:

.
./foo
./bar

but with ./ which I don't want. Is there a way to get find to output just the raw names?

I tried sending the list to stat to format it but that just gives me the same result:

find . -type d -maxdepth 1 -print0 | xargs -0 stat -f '%N'

Answer 1

With GNU find you can use the -printf option:

find . -maxdepth 1 -type d -printf '%f\n'

Answer 2

Update:

A shorter alternative:

 find . -maxdepth 1 -type d | cut -c 3-

Will give you the names, one per line, without any slashes

Answer 3

Let sed remove those two characters:

find . -maxdepth 1 -type d | sed -e 's/^\.\///'

Answer 4

I usually use:

find * -type d

But I don't know if it's the right way to do what you want.

Answer 5

Using GNU find, you can use -mindepth to prevent find from matching the current directory:

find . -type d -maxdepth 1 -mindepth 1

Since you are not doing this recursively, you can use a bash glob:

echo */

Adding a trailing / to a glob will cause only directories to be matched.