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Is there a more compact form of killing background jobs than:

for i in {1..5}; do kill %$i; done

Also, {1..5} obviously has a hard-coded magic number in it, how can I make it "N" with N being the right number, without doing a:

$(jobs | wc -l)

I actually use \j in PS1 to get the # of managed jobs, is this equivalent?

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kill $(jobs -p) seems easier. –  jw013 Jul 19 '12 at 22:00
I would prefer to kill jobs individually, if possible. (I might have misunderstood your comment, though) –  Robottinosino Jul 19 '12 at 22:12
for pid in $(jobs -p); do kill $pid; done? –  jw013 Jul 19 '12 at 22:27
@jw013 It's not only easier, it's actually correct (please post it as an answer), unlike a solution based on counting the lines of the output of jobs which only works if the jobs happen to be numbered consecutively. Oh, and “kill jobs individually” is meaningless: passing multiple PIDs to the kill command does exactly the same thing as passing them separately. –  Gilles Jul 19 '12 at 23:52
I was entering the command incorrectly, kill $(jobs -p) words and looks very correct to me too. Ready to accept. –  Robottinosino Jul 20 '12 at 0:31

1 Answer 1

up vote 6 down vote accepted

To just kill all background jobs managed by bash, do

kill $(jobs -p)

Note that since both jobs and kill are built into bash, you shouldn't run into any errors of the Argument list too long type.

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For posterity, with zsh it would be jobs -p | awk '{print $3}' | xargs kill. ZSH isn't better at everything. –  bahamat Jul 22 '12 at 18:54
Also for posterity, what bahamat thinks is the way to do it in zsh disqualifies them as any authority on the topic. –  user112553 Mar 8 '13 at 23:46
I feel like I should know this, but how does the '$' work here? –  fersarr Jan 8 at 17:21
@fersarr Here you go –  jw013 Jan 8 at 21:27

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