Print folders names character count

Question

I am trying to use find . -type d -print | wc -m where -m or --chars would print the character counts of the folder names.

Take following screen shot as example, the character count for tempFolder + tempFolder + dingdongFolder is only 34, and event counting the slashes and dots is still 40. Why the command print out 43 characters? Where are the 3 extra characters come from?

Answer 1

find . -type d -print | tr -d '\n' | wc -m

tr will delete all newline characters and wc will count number you want.

Answer 2

Apparently trailing newlines are counted as a character also.

Suppose you want the character count per directory, you can do

$ find -type d -exec bash -c 'echo -n $0 | wc -m' {} \; 
1
12
27

Which adds up to the 40 that you are looking for. Note that the echo -n removes the trailing newlines.

Summing these three is also possible.

$ find -type d -exec bash -c 'echo -n $0 | wc -m' {} \; | awk '{S+=$1} END  {print(S)}'
40

Answer 3

Set a bash/ksh/zsh array ct to the output of wc -lm, then use shell arithmetic.

ct=($(find . -type d -print |wc -lm)); echo $((ct[1]-ct[0]))

Or use field splitting and positional parameters:

set $(find . -type d -print |wc -lm); echo $(($2 - $1))