Tell me more ×
Unix & Linux Stack Exchange is a question and answer site for users of Linux, FreeBSD and other Un*x-like operating systems.. It's 100% free, no registration required.

At best I would like to have a call like this:

$searchtool /path/to/search/ -contained-file-name "*vacation*jpg"

... so that this tool

  • does a recursive scan of the given path
  • takes all files with supported archive formats which should at least be the "most common" like zip, rar, 7z, tar.bz, tar.gz ...
  • and scan the file list of the archive for the name pattern in question (here *vacation*jpg)

I'm aware of how to use the find tool, tar, unzip and alike. I could combine these with a shell script but I'm looking for a simple solution that might be a shell one-liner or a dedicated tool (hints to GUI tools are welcome but my solution must be command line based).

share|improve this question

1 Answer

up vote 1 down vote accepted

(Adapted from How do I recursively grep through compressed archives?)

Install AVFS, a filesystem that provides transparent access inside archives. First run this command once to set up a view of your machine's filesystem in which you can access archives as if they were directories:

mountavfs

After this, if /path/to/archive.zip is a recognized archive, then ~/.avfs/path/to/archive.zip# is a directory that appears to contain the contents of the archive.

find ~/.avfs"$PWD" \( -name '*.7z' -o -name '*.zip' -o -name '*.tar.gz' -o -name '*.tgz' \) \
     -exec sh -c '
                  find "$0#" -name "*vacation*.jpg"
                 ' {} 'Test::Version' \;

Explanations:

  • Mount the AVFS filesystem.
  • Look for archive files in ~/.avfs$PWD, which is the AVFS view of the current directory.
  • For each archive, execute the specified shell snippet (with $0 = archive name and $1 = pattern to search).
  • $0# is the directory view of the archive $0.
  • {\} rather than {} is needed in case the outer find substitutes {} inside -exec ; arguments (some do it, some don't).

Or in zsh ≥4.3:

mountavfs
ls -l ~/.avfs$PWD/**/*.(7z|tgz|tar.gz|zip)(e\''
     reply=($REPLY\#/**/*vacation*.jpg(.N))
'\')

Explanations:

  • ~/.avfs$PWD/**/*.(7z|tgz|tar.gz|zip) matches archives in the AVFS view of the current directory and its subdirectories.
  • PATTERN(e\''CODE'\') applies CODE to each match of PATTERN. The name of the matched file is in $REPLY. Setting the reply array turns the match into a list of names.
  • $REPLY\# is the directory view of the archive.
  • $REPLY\#/**/*vacation*.jpg matches *vacation*.jpg files in the archive.
  • The N glob qualifier makes the pattern expand to an empty list if there is no match.
share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.