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How can I sort of list current directory contents (including sub-directories recursively) (which is under svn) files info (path relative to current dir)?

I want this to get log in format like:

none|main.lua
none|src/main.h

I wonder if it is possible and how to do such thing using svn and bash?

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I want to create such log in order to create an image using gource that would represent actual state or current revision svn files. so I would just add none as user name, 0 as timestamp, A as type. –  user1078642 May 26 '12 at 22:37
    
if it's just the relative path, have you considered using find? For the relative path, with bash you have the globstar (disabled by default, but just a shopt -s globstar away). –  njsg May 26 '12 at 23:02
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I don't understand whether you're trying to list all files in your working copy or just the files under svn, nor where the none comes from (why not a user name? and why do you mention a timestamp and a type in your comment, there aren't any in your sample output). –  Gilles May 28 '12 at 1:19
    
If you need this for gource, the wiki of gource has a page that explains how to use it with subversion code.google.com/p/gource/wiki/SVN –  janos Aug 22 '12 at 9:02
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1 Answer

up vote 1 down vote accepted

You may want to start with something like:

find . -name .svn -prune -o -print

This prints out all the files under ., without traversing into any .svn directories. I don't know what the none| part means, but you can pipe the output of find into sed, etc..

Another way is to start with

svn status -v

and filter the output as ncecssary.

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