Execute a command for each entry in a file

Question

How can I execute a command for file which has address of jar files. The command that I want to execute is jar xf entry.jar. I d like to execute that command and sent the outputs to another file.

Assume my file contains following entries.

a.jar
b.jar
c.jar

What I want is simply extract these jar files and sent the output to another file.

Answer 1

I guess what you want is something like this:

xargs -n1 -d'\n' jar xf <list

Where list is the name of the file containing entries.

I'm not sure what you mean by send the outputs to another file. If you want a record of what the jar command prints on the console you can append a >out.log argument at the end.

(The -d option is there in the case filenames contains spaces and are listed one per line.)

Answer 2

Maybe

for entry in $(<list) ; do jar -xf "$entry"; done > output2.log

works for you?

jar -xf a b [...]

would try to extract b from a, but you want to extract all 3 jars, as far as I can see.