Delete lines from a file

Question

I have a file where data is present in below format :

cat file.txt
02|123
04|321
08|453
09|364
01|789
23|765

so here 02,04 ... represents Hour and 123,321 ... represents some random value.

I want to delete all the lines from this file where first two value is less than the current hour which will get from date +'%H'.

Suppose current hour is 10 so i want to delete lines containing first two less than 10 i.e

you can modify the answer for THIS QUESTION to suit your needs. Just use awk -F "|" to specify your field delimiter and compare the $1 to the current hour as in that answer — MelBurslan, Mar 10, 2016 at 18:26

steeldriver · Accepted Answer · 2016-03-10 19:50:05Z

6

#!/bin/bash
HOUR=`date +%H`
awk -v hour=$HOUR -F"|" '{if($1 >= hour)print}' file.txt > newfile.txt
mv newfile.txt file.txt

steeldriver

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answered Mar 10, 2016 at 18:39

user1700494

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2

You could simplify that to awk -v hour=10 -F"|" '$1 >= hour' ... (since print is awk's default action)
– steeldriver
Mar 10, 2016 at 19:51

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