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For a large logging file, how do I display those lines without "success" or not terminated with "ok"?

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grep -Ev '(success|ok$)' – jordanm Mar 2 at 18:48
@jordanm was going to suggest the same. This is an answer though and should be put in the right section. – val0x00ff Mar 2 at 18:59
@jordanm terrific, please make it an answer – Lee Mar 2 at 19:19
up vote 13 down vote accepted

To remove lines that contain either string, specifically with grep:

  • In one command, per jordanm's comment:

    grep -Ev 'success|ok$'


    grep -ve success -e 'ok$'


    grep -v 'success
  • In two commands:

    grep -v success file | grep -v 'ok$'


$ cat file
success something else
success ok
just something else

$ grep -Ev 'success|ok$'
just something else
$ grep -v success file | grep -v 'ok$'
just something else

To remove lines that contain both strings, specifically with grep:

grep -v 'success.*ok$' file


$ cat file
success something else
success ok
just something else

$ grep -v 'success.*ok$' file
success something else
just something else
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if jordanm wants to answer instead, I'll delete this one. – Jeff Schaller Mar 2 at 19:15
No, this is fine. – jordanm Mar 2 at 19:21
Lee, I see you've accepted this answer, but I want to clarify - these greps will remove lines that contain either of those two strings; did you want to remove only lines that contain both "success" and end with "ok" ? – Jeff Schaller Mar 2 at 19:43
No. either, not both. – Lee Mar 2 at 19:58
thanks for clarifying; take a look at the most recent edit to your question to make sure it says what you meant. – Jeff Schaller Mar 2 at 20:00

I would try awk

awk '/success/ { next ; } /ok$/ { next ; } { print ;}' file


  • /success/ { next ; } find word success and skip line
  • /ok$/ { next ; } find lower case ok and skip line
  • { print ;} implicit else : print line

as per suggestion

short awk (thanks to Stéphane Chazelas )

awk '!/success/ && !/ok$/'

which is basically not (success) and not (ok at end of line )

golfed awk (thank to cas )

awk '! /success|ok$/'

which reuse regexp, and negate it

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Even if this works, that's not an answer to the question. – Quora Feans Mar 2 at 18:57
Yes, it's an alternative way. – Lee Mar 2 at 19:25
@Lee: it's not an alternative. It does not fulfill the condition "use grep to." – Quora Feans Mar 2 at 19:31
awk '!/success/ && !/ok$/' would be more canonical. – Stéphane Chazelas Mar 2 at 22:00
or even awk '! /success|ok$/' – cas Mar 3 at 1:27

Adding to grep -Ev commands above: You can use egrep -v 'success|ok$' filename

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egrep is deprecated in favor of grep -E – Dani_l Mar 3 at 11:39

Since awk was mentioned, another alternative would be sed:

sed '/success/d;/ok$/d' file
sed -e '/success/d' -e '/ok$/d' file

or (Newer sed and future POSIX) thanks to Stéphane Chazelas

sed -E '/success|ok$/d' file
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If you change sed -r to sed -E, then that will work in some BSD sed in addition to (not too old versions of) GNU sed. sed -E will be in the next major issue of the POSIX spec. – Stéphane Chazelas Mar 3 at 10:06

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