I am running ltib Linux on P1022RDK (P1022 Core) platform. I have 512 MB = 0x20000000 memory. I want my Linux kernel to use the second half of the board memory (i.e from 256 MB to 512 MB) and want the first half of memory to be reserved for some other purpose.
For this I am building the Linux kernel using ltib, and setting the following kernel configuration. Please suggest if I am doing it the right way.
CONFIG_LOWMEM_SIZE = 0x10000000 # 256 MB CONFIG_PHYSICAL_START = 0x10000000 # Starting from 256MB (second half of memory)
On the Uboot I am loading the kernel the following way:
setenv loadaddr 0x11000000 # Kernel base = 0x10000000 + 0x01000000 (offset) setenv fdtaddr 0x10c00000 # Kernel base = 0x10000000 + 0x00c00000 (offset) bootm $loadaddr - $fdtaddr My kernel Load address is 0x10000000 & kernel entry point is 0x10000000
Using the above configuration/steps my kernel is stuck at the following on Uboot:
Booting kernel from Legacy Image at 11000000 ... Image Name: Linux-18.104.22.168 Image Type: PowerPC Linux Kernel Image (gzip compressed) Data Size: 3352851 Bytes = 3.2 MB Load Address: 10000000 Entry Point: 10000000 Verifying Checksum ... OK Flattened Device Tree blob at 10c00000 Booting using the fdt blob at 0x10c00000 Uncompressing Kernel Image ... OK
It should uncompress FDT here & continue