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Given a variable name is there a function that will print its value?

Often times I pass the name of a variable to a bash function and instead of doing the expansion while passing it I would like to expand it inside the function. Of course when I do this I end up having to create the string with the variable name then running exec. It would be much more succinct if I could just run a command that echoed the output!

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Not sure what you mean. Can you provide an example? –  forcefsck Oct 28 '11 at 15:06

2 Answers 2

up vote 6 down vote accepted
show_val() { echo "${!1}"; }
foo=bar
echo $(show_val foo)   # => bar
# works with arrays too
a=(zero one two)
echo $(show_val a[1])  # => one

Documented in the bash manual here

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As always Ty for the guidance. –  James Andino Oct 28 '11 at 18:48

Not sure what you mean in your question about "running exec". Perhaps you meant eval.

show_val() { eval echo \$$1; }
foo=bar
show_val foo
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