Getting size with du of files only

Question

How can I get the size of all files and all files in its subdirectories using the du command.

I am trying the following command to get the size of all files (and files in subdirectories)

find . -type f | du -a

But this prints out the folder sizes as well. How can I get a listing of sizes of all files and files in subdirectories? I also tried the exec flag but I am not sure how to pipe the output into another command after it executes the results of find into du.

Sorry should have mentioned this before, the operating system is AIX 6.1 with ksh shell.

Thank you.

Answer 1

I usually use the -exec utility. Like this:

find . -type f -exec du -a {} +

I tried it both on bash and ksh with GNU find. I never tried AIX, but I'm sure your version of find has some -exec syntax.

The following snippet sorts the list, largest first:

find . -type f -exec du -a {} + | sort -n -r | less

Answer 2

If you have GNU utilities, try

find . -type f -print0 | du --files0-from=-

Answer 3

I generally use:

find . -type f -print0 | xargs -r0 du -a

Xargs usually calls the command, even if there are no arguments passed; xargs du </dev/null will still be called, xargs -r du </dev/null will not call du. The -0 argument looks for null-terminated strings instead of newline terminated.

Then I usually add | awk '{sum+=$1} END {print sum}' on the end to get the total.

Answer 4

Here's a version with long parameter names and human sorting.

find . -type f -exec du --human {} + | sort --human --reverse | head

I also saw no need for -a/--all to be passed to du.