How to execute script on logging out?

Question

I'm reading The Unix Programming Environment. There is an exercise question to print how much CPU time you have consumed when you log off by editing .profile.

I tried with this

trap 'times' 0 1 2 15

but it is not working.

Answer 1

In bash, the ~/.bash_logout file will be executed upon exiting a login shell. Put your code in that file.

Answer 2

From the tag, I'm guessing that this is in bash. Bash defaults to .bash_profile and only uses .profile if the former does not exists. Try putting the trap line in .bash_profile.

Alternatively, you could put the following in .bash_logout:

times
read -t 5 # timeout after 5 seconds