Number of words from a file with the Linux shell

Question

How do I find and many words of a file with the Linux shell?

I have

text
example

text
example

text
example

text
example

And I need

text
example1

text
Example2

text
example3

text
example4

That is, the word is located and then numbers.

Answer 1

I don't completely understand your question. However provided your input example and your output example you can do something like this (just an orientation):

Your input file named "example" is as follows:

text
example

text
example

text
example

text
example

So provided that "text" can be any thing in a line, and "example" is just "example" (edit my code to fit your needs); you can match your output requirements with the following statement (not too much exhaustive however):

hmontoliu@ulises:/tmp$ awk 'BEGIN {c=0} {if ( $0 ~ /example/ ) {c+=1; print $0c} else print $0}'   example 
text
example1

text
example2

text
example3

text
example4

HTH

Answer 2

What you say and what you demonstrate seem to contradict each other. If you truly want to count the number of words in a file, you can use wc -w. However, your initial question looks more like you want line numbers, which you can get through any of the following methods, with varying degrees of portability:

cat -n [file]
nl [file]
awk '{print FNR "\t" $0}' [file]
sed = [file] | sed 'N;s/\n/ /'

Answer 3

As I understand from example you want to print lines and after that line number.

For printing line number and then lines you can use cat or nl:

$ cat -n test.txt 
     1  text example
     2  text example
     3  text example
     4  text example

$ nl test.txt 
     1  text example
     2  text example
     3  text example
     4  text example

But there is no possibility to print numbers after lines in cat and nl so you can use awk:

$ awk '{print $0 "\t" NR}' test.txt 
text example    1
text example    2
text example    3
text example    4