Take the 2-minute tour ×
Unix & Linux Stack Exchange is a question and answer site for users of Linux, FreeBSD and other Un*x-like operating systems.. It's 100% free, no registration required.

Say I have folder "foo" residing, the home directory. I want to get some info of it, owner, group, permissions, etc...

I then do this to try to get the information:

cd ~
ls -l foo

Of course it now lists the info of the contents of "foo"

Then I could do something like this

cd ~
dir=foo
ls -l $foo/.. | awk 'BEGIN { dir="'$foo'" } { if($9 == dir) { print $0 }  }'

But isn't there an easier way to do this?

share|improve this question

migrated from stackoverflow.com Aug 19 '11 at 16:24

This question came from our site for professional and enthusiast programmers.

1 Answer 1

up vote 11 down vote accepted

Try

ls -ld foo

And you will get what you want.

But also consider stat if you want to capture information. The output of ls is for human consumption only.

stat -c %U foo # get owner of foo
share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.