Most efficient way to run 2 while loops

Question

Currently I use two different while loops to start my window manager, dwm, and the status bar that prints system info to it.

My solution at the moment is to run them consecutively in the same script, like so:

while true; do
        $HOME/Scripts/dwm-status
        sleep 2s
    done &
while true; do
    dwm >/dev/null
done

I have also seen it run as a nested while loop, like this:

while true; do
        while true; do
            $HOME/Scripts/dwm-status
            sleep 2s
        done &
        dwm >/dev/null
    done

The second seems to cause CPU spikes. In terms of efficiency (least call on resources etc.,) what is the best approach to run these two loops and why?

Answer 1

I'm not sure if I'm pointing out something obvious, but the first way is creating two loops that run forever, while the second is creating an infinite loop that creates infinite loops, so you're going to end up with an ever-increasing number of infinite loops. It creates an infinite loop, runs dwm, and then creates another infinite loop -- the first infinite loop hasn't stopped. Each pass will make another dwm-status loop, even though the others are already running (while true will keep them running indefinitely)