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I just thought I might get version information about the current bash by entering

bash -v

That brought many lines of code to stdout and left me with a line that appears right above my usual promt

printf "\033]0;%s@%s:%s\007" "${USER}" "${HOSTNAME%%.*}" "${PWD/#$HOME/~}"
[foo@bar path]$

I think I have a tiny clue what this might be (the code that renders how the prompt looks like), but I have no idea whatsoever how to get rid of this. Who does?

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up vote 6 down vote accepted

Simply type exit to get out of the new bash shell you invoked.


The -v option doesn't do what you think. From bash(1):

-v Display readline variable names and values in such a way that they can be re-read.

So what your command does is start another bash shell with the -v option that prints the various variable names you see in your output.

What you want is

bash --version


Since the OP commented that this sounds too much like a "restart your system" kind of answer, here's an alternative way:

Disable the -v option by issuing

set +v

Note, though, that this will leave you in the child shell you forked earlier by calling bash.

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Thanks, that did the job. I was afraid this might stay... – Gottlieb Notschnabel May 2 '14 at 1:00
@GottliebNotschnabel Please accept the answer then so that everyone can see this question is done. – Hauke Laging May 2 '14 at 2:40
@HaukeLaging Yeah, sorry for not having accepted this earlier. But I posed this question yesterday before I went to bed. Now I saw the answer (which helped me) and I wanted to accept it, but would have had to wait another 6 minutes before I could accept. So I postponed accepting to the next day. I apologize. – Gottlieb Notschnabel May 2 '14 at 12:17
I like this answer because it's just like 99% of all IT problem solving advices: "Restart your system!" :-) – Gottlieb Notschnabel May 2 '14 at 12:18
@GottliebNotschnabel Please see the update :) – Joseph R. May 2 '14 at 12:26

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