How to get some part of string in linux

Question

The output of find command is like

/home/user/test/folder1/abc.png

Now i want to get

folder1

from above string

Answer 1

Are you looking for that part of the path based on a fixed location from the left of the path or fixed depth from the right? If you are looking from the left you can do this easily with cut by using '/' as a field separator and grabbing the fourth field like this:

find ... | cut -d/ -f4

Answer 2

If you want "folder1", then type "folder1" ...

---

If you want the second-to-last path component, this works in both sh and bash:

dir=${path%/*}
dir=${dir##*/}

(assuming $path contains the full path)

Answer 3

Here's my try:

find . -name abc.png -exec dirname {} \; |grep -o '[^/]*$'

Answer 4

path=/home/user/test/folder1/abc.def
folder=$(basename $(dirname $path))

or, if you want to operate on the output of find (i.e. several paths, one per line)

find ... | awk -F/ '{print $(NF-1)}'
find ... | sed 's#.*/\([^/]*\)/[^/]*$#\1#'

Answer 5

I would use awk.

Something like:

find /home -name "abc.png" | awk -F"/" '{print $5}'