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How would I copy (archive style where date isn't changed) all the files in a backup directory to the user's directory while renaming each file to remove the random string portion from the name (i.e., -2b0fd460_1426b77b1ee_-7b8e)?

cp from:

/backup/path/data/Erp.2014.02.16_16.57.03-2b0fd460_1426b77b1ee_-7b8e.etf

to:

/home/user/data/Erp.2014.02.16_16.57.03.etf

Each file will always start with "Erp." followed by the date-time stamp string followed by the random string and then the extension ".etf". I want to keep all name elements including the date-time stamp. I just want to remove the random string.

The random string allows multiple backups of the same file. However, in this case, I just ran fdupes and there are no duplicates. So I can simply restore all the files, removing the random string.

I'm looking for a one-line bash command to do it.

If that won't work, I could do it in two or more steps. I normally use KRename, but in this case I need to do it in bash. (I'm working remotely.)

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4 Answers 4

up vote 3 down vote accepted

pax can do this all at once. You could do:

cd /backup/path/data && pax -wrs'/-.*$/.etf/' Erp*etf /home/user/data

pax preserves times by default, but can add -pe to preserve everything (best done as root) or -pp to preserve permissions , eg:

cd /backup/path/data && pax -wrs'/-.*$/.etf/' -pe Erp*etf /home/user/data

Otherwise (pax isn't usually available by default), surely it is better to do a copy then a rename:

cp -a /backup/path/data/Erp*.etf /home/user/data
rename 's/-.*$/.etf/' /home/user/data/Erp*.etf

This way there is not a different process started for each file.

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I can see that I need to become familiar with pax. This looks like a very useful tool. Makes me wonder why it isn't standard in more distros... –  MountainX Feb 20 at 1:46
    
@MountainX, Good question, according to Wikipedia, pax has been in the Linux Standard Base since 2005. Plus the would be alternative for this, GNU cpio, is possibly the least featureful GNU tool in existence. –  Graeme Feb 20 at 11:49
    
+1 for your last solution and This way there is not a different process started for each file. But rename is different on Fedora/Red Hat: I don’t know how to use it in this case. –  erik Feb 20 at 19:14
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You can use the cp command with the -a option

-a, --archive
       same as -dR --preserve=all

And then use a for loop to rename all files while copying them:

for file in Erp*etf; do
  cp -a $file destinationDirectory/${file%%-*}.etf
done

Ready. Start this command in the source directory.

Explanation: The %%-* will cut off all the characters after the first occurence of a hyphen/minus - and the .etf at the end again adds the file extension.

Well, and as a one liner, put it all in one line. :-) Like this

for file in Erp*etf; do cp -a $file destinationDirectory/${file%%-*}.etf; done
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cp doesn't have that capability. I recall cpio being able to do that, but the current manpage says otherwise. However, (gnu) tar does have a --transform option:

 --transform, --xform EXPRESSION
       use sed replace EXPRESSION to transform file names

So you'd have a cmdline like:

(cd /backup/path/data; tar --create --transform 's/-.*-....//' .) | (cd /home/user/data; tar --extract)
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In zsh, use zmv. Put this in your .zshrc:

autoload -U zmv
alias zcp='zmv -C'
alias zln='zmv -L'

Then use

zcp '/backup/path/data/(*)-[0-9A-Fa-f_]#.(*)' '/home/user/data/$1$2'

In bash:

zsh -c 'autoload zmv; zmv -C $0 $1' '/backup/path/data/(*)-[0-9A-Fa-f_]#.(*)' '/home/user/data/$1$2'

If you don't have zsh, a POSIX way uses pax (this copies directories recursively).

If you're on a restricted system with no zsh and no pax, you can use a loop:

for source in /backup/path/data/*-*.etf; do
  basename=${source##*/}
  cp "$source" "/home/user/data/${basename%-*}.${basename##*.}"
done
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